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SOLUTION: A sample of 400 racing cars showed that 80 cars cost …

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    A sample of 400 racing cars showed that 80 of them cost over $700,000. What is the 99% confidence interval for the true proportion of racing cars that cost over $700,000? Give an interpretation for this confidence interval. Best Answer. This is the best answer based on feedback and ratings. 100% (5 ratings) q=0.8, n=400 (a,b)= *=.2+- (2.576*. ….

SOLUTION: A sample of 400 racing cars showed that 80 cars cost …

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    Question 465515: A sample of 400 racing cars showed that 80 cars cost over $700,000. What is the 99% confidence interval of the true proportion of cars costing over $700,000? Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!, q=0.8, n=400

A sample of 400 racing cars showed that 80 of them cost …

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    A sample of 400 racing cars showed that 80 of them cost over $700,000. What is the 99% confidence interval for the true proportion of racing cars that cost over $700,000?

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    Math. Statistics and Probability. Statistics and Probability questions and answers. A sample of 400 racing cars showed that 80 cars cost over $700,000, what is the 99% confidence interval of the true proportion of cars costing over $700,000? …

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    A sample of 400 racing cars showed that 80 cars cost over $700,000. What is the 99% confidence interval estimate - Answered by a verified Math Tutor or Teacher. We use cookies to give you the best possible experience on our website.

(Solved) - A sample of 400 racing cars showed that 80 of …

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    A sample of 400 racing cars showed that 80 of them cost over $700,000. What is the 99% confidence interval for the true proportion of racing cars that cost over $700,000? Give an interpretation for this confidence interval. 1 Approved Answer. Lovish s …

BA275 Assignment 3 Flashcards - Quizlet

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    c) Answer part (b) for a sample of 1600. Put 1600 in place of 800 in the calculations a) Show the sampling distribution of p, the sample proportion of households spending more than $100 per week on groceries. The mean of the sample means = 0.17 The standard deviation of the sample means = sqrt[0.17*0.83/800]

Unit Test review questions Flashcards - Quizlet

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    A racecar driver has a 0.05 probability of winning any given race in a season. There are 16 races in a season, and whether or not the driver wins one race is independent of whether he wins any other race. ... Her campaign manager polled a random sample of 400 likely voters before the debate and a random sample of 500 likely voters after the ...

AP STATISTICS 2010 SCORING GUIDELINES

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    of this binomial distribution are the sample size, n, which has a value of n = 2,000, and the proportion of new car buyers who bought model E, p, which has a value of 2,323 0.0078. 297,354 p =≈ The expected value of the number of model E buyers in a simple random sample of 2,000 is therefore npnp p() so the standard deviation is 15.50 3.94.≈

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